document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156578>Question 156578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice it's width.  If the perimeter of the rectangle is 48 cm, find it's area.  I came up with 24 cm.  could some review and let me know if I did this right..thanks upfront.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115352 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's start by finding the length, L, and the width, W.<BR>\n" );
document.write( "We are told that:<BR>\n" );
document.write( "L = 2W \"The length is twice its (no apstrophe here, please) width\" and we are also told that:<BR>\n" );
document.write( "P = 48 \"The perimeter is 48cm.<BR>\n" );
document.write( "The perimeter is found by:<BR>\n" );
document.write( "P = 2(L+W) Replace the L here with the L from the first equation (L = 2W) and the P with 48cm.<BR>\n" );
document.write( "48 = 2(2W+W) Simplify.<BR>\n" );
document.write( "48 = 6W Divide both sides by 6.<BR>\n" );
document.write( "W = 8cm and L = 2(8) = 16cm.<BR>\n" );
document.write( "Now you can find the area because:<BR>\n" );
document.write( "A = L*W<BR>\n" );
document.write( "A = 16*8<BR>\n" );
document.write( "A = 128 sq.cm<BR>\n" );
document.write( " </SPAN>\n" );
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