document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156578>Question 156578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice it's width.  If the perimeter of the rectangle is 48 cm, find it's area.  I came up with 24 cm.  could some review and let me know if I did this right..thanks upfront.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115345 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 2 * w.\r<BR>\n" );
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document.write( "if w = width then l = length = 2w.\r<BR>\n" );
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document.write( "p = perimeter = 48 cm.\r<BR>\n" );
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document.write( "perimeter = 2*l + 2*w.\r<BR>\n" );
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document.write( "since l = 2w, then perimeter = 2*(2w) + 2*w.\r<BR>\n" );
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document.write( "4w + 2w = 6w = 48, so w = 48/6 = 8 cm.\r<BR>\n" );
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document.write( "if w = 8 cm, then l = 2w = 16 cm.\r<BR>\n" );
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document.write( "area of a rectangle is length * width = 8 * 16 = 128 cm.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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