document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156530>Question 156530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 180 cm, what is the length of the diagonal? \r<BR>\n" );
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document.write( "Note: Your answer must be a number. It may not contain any arithmetic operations. \r<BR>\n" );
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document.write( "The length of the diagonal is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115338 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=2L-6<BR>\n" );
document.write( "L(2L-6)=180<BR>\n" );
document.write( "2L^2-6L-180=0<BR>\n" );
document.write( "2(L^2-3L-90)=0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"L+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "L=(3+-SQRT[-3^2-4*1*-90])/2*1<BR>\n" );
document.write( "L=(3+-SQRT9+360])/2<BR>\n" );
document.write( "L=(3+-SQRT369)/2<BR>\n" );
document.write( "L=(3+-19.21)/2<BR>\n" );
document.write( "L=(3+19.21)/2<BR>\n" );
document.write( "L=22.21/2<BR>\n" );
document.write( "L=11.1 cm. IS THE LENGTH.<BR>\n" );
document.write( "W=2*11.1-6<BR>\n" );
document.write( "W=22.2-6<BR>\n" );
document.write( "W=16.2 cm. IS THE WIDTH.<BR>\n" );
document.write( "C^2=11.1^2+16.2^2<BR>\n" );
document.write( "C^2=123.21+262.44<BR>\n" );
document.write( "C^2=385.65<BR>\n" );
document.write( "C=SQRT385.65<BR>\n" );
document.write( "C=19.64 cm. LENGTH OF THE DIAGONAL. </SPAN>\n" );
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