document.write( "Question 156565: 9. Using Factoring, how do I complete this exercise?\r
\n" ); document.write( "\n" ); document.write( "25x^2 + 20x + 4\r
\n" ); document.write( "\n" ); document.write( "thank you!
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Algebra.Com's Answer #115315 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
None of the coefficients have anything in common besides 1. So, we are going to need a 5 coefficient for a,c in (ax+b)(cx+d) factorization.
\n" ); document.write( "So we need (5x+b)(5x+d)=25x^2+20x+4. We can suspect b=d=2 because if b=4, our x coefficient becomes >20. So (5x+2)^2 is our factorization.\r
\n" ); document.write( "\n" ); document.write( "Now, we could solve this slightly differently, yet more concisely:\r
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\n" ); document.write( "\n" ); document.write( "(5x+b)(5x+d)=25x^2+20x+4
\n" ); document.write( "25x^2+5xd+5xb+bd=25x^2+20x+4\r
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\n" ); document.write( "\n" ); document.write( "This means that:
\n" ); document.write( "5d+5b=20
\n" ); document.write( "bd=4\r
\n" ); document.write( "\n" ); document.write( "from the first equation: d=4-b
\n" ); document.write( "putting that into the second equation: b(4-b)=4
\n" ); document.write( "4b-b^2-4=0
\n" ); document.write( "b^2-4b+4=0\r
\n" ); document.write( "\n" ); document.write( "We must necessarily have solution b=2 and d=4-2=2 as well. So we place those values in our hybrid form, getting the answer already supplied.
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