document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156520>Question 156520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve.<BR>\n" );
document.write( "Not sure how to write square root, \r<BR>\n" );
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document.write( "(square root 3x+24) = x+2\r<BR>\n" );
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document.write( "I know a sqiare root is the opposite of exponent 2, not sure how to work this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115295 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (square root 3x+24) = x+2 <BR>\n" );
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document.write( "Square boh sides:<BR>\n" );
document.write( "3x + 24 = (x+2)^2<BR>\n" );
document.write( "3x + 24 = x^2 + 4x + 4<BR>\n" );
document.write( "x^2 +x -20 = 0<BR>\n" );
document.write( "(x+5)(x-4) = 0<BR>\n" );
document.write( "x = -5 or x = 4<BR>\n" );
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document.write( "Check these answers in sqrt(3x+24) = x+2:<BR>\n" );
document.write( "x = -5 ? : sqrt(-15+24) = -5+2 = sqrt(9) = 3 : OK<BR>\n" );
document.write( "x = 4 ? : sqrt(12+24) = 6 : OK<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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