document.write( "Question 156483: 2 cars race around a circular track, in opposite directions, at constant speeds. They start at the same point and meet every 30.0 seconds. If they move in the same direction, they meet every 120.0 seconds. If the track is 1800 meters long, what is the speed of each car? \n" ); document.write( "
Algebra.Com's Answer #115291 by ankor@dixie-net.com(22740)\"\" \"About 
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2 cars race around a circular track, in opposite directions, at constant speeds.
\n" ); document.write( " They start at the same point and meet every 30.0 seconds. If they move in the
\n" ); document.write( " same direction, they meet every 120.0 seconds. If the track is 1800 meters
\n" ); document.write( " long, what is the speed of each car?
\n" ); document.write( ":
\n" ); document.write( "Change seconds to min in the problem
\n" ); document.write( ":
\n" ); document.write( "Let a = speed of car a (in meters/min)
\n" ); document.write( "Let b = speed of car b
\n" ); document.write( ":
\n" ); document.write( ".5(a+b) = 1800
\n" ); document.write( "Multiply equation by 2
\n" ); document.write( "a + b = 3600
\n" ); document.write( ":
\n" ); document.write( "2(a-b) = 1800
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "a - b = 900
\n" ); document.write( ":
\n" ); document.write( "a + b = 3600
\n" ); document.write( "a - b = 900
\n" ); document.write( "--------------adding eliminates b
\n" ); document.write( "2a = 4500
\n" ); document.write( "a = \"4500%2F2\"
\n" ); document.write( "a = 2250 meters/min (\"%282250%2A60%29%2F1000\" = 135 km/hr)
\n" ); document.write( ":
\n" ); document.write( "Find the speed of b
\n" ); document.write( "a + b = 3600
\n" ); document.write( "a + 2250 = 3600
\n" ); document.write( "a = 3600 - 2250
\n" ); document.write( "a = 1350 meters/min (\"%281350%2A60%29%2F1000\" = 81 km/hr)
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