document.write( "Question 156475: Problem- I have 50,000 gallons of water. If the water is stored in a sphere, what must the radius of the sphere be? I'm trying to figure out the steps and conversions necessary to answer this problem. \n" ); document.write( "

Algebra.Com's Answer #115273 by gonzo(654) $\"\"$ $\"About$

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from the internet it was determined that 7.48 gallons of water equals 1 cubic foot in volume.\r
\n" ); document.write( "\n" ); document.write( "this translates to .13368984... cubic feet per gallon of water.\r
\n" ); document.write( "\n" ); document.write( "you have 50000 gallons of water so the volume would be 50000 * .13368984... = 6684.49491979... cubic feet.\r
\n" ); document.write( "\n" ); document.write( "to put it in a sphere you then take the formula for the volume of a sphere and works backwards to get the radius of the sphere.\r
\n" ); document.write( "\n" ); document.write( "formula for volume of a sphere is 4/3 * pi * r^3.\r
\n" ); document.write( "\n" ); document.write( "formula becomes volume = 6684.4949... cubic feet = 4/3 * pi * r^3\r
\n" ); document.write( "\n" ); document.write( "becomes r^3 = 6684.4949 ... / ( 4/3 * pi )\r
\n" ); document.write( "\n" ); document.write( "becomes r^3 = 1595.804911 cubic feet.\r
\n" ); document.write( "\n" ); document.write( "becomes r = cube root of 1595.804911\r
\n" ); document.write( "\n" ); document.write( "becomes r = 11.6858... feet.\r
\n" ); document.write( "\n" ); document.write( "pi is a constant with value of 3.141592654...\r
\n" ); document.write( "\n" ); document.write( "radius is 11.6858... feet.\r
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