document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23095>Question 23095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i show my work for this problem step by step here it is:<BR>\n" );
document.write( "e^ln5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11527 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon%21><B>stanbon!(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon%21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let y=e^(ln5)<BR>\n" );
document.write( "Take the ln of both sides to get:<BR>\n" );
document.write( "lny = (ln5)(lne)<BR>\n" );
document.write( "But lne=1, therefore<BR>\n" );
document.write( "lny = ln5<BR>\n" );
document.write( "Take the anti-log of both sides to get:<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "Therefore e^(ln5) = 5\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );