document.write( "Question 156220: Please help me solve this problem::\r
\n" ); document.write( "\n" ); document.write( "There is $65.00 in dimes and quarters. If there is 389 coins how many were dimes and how many were quarters?\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #115268 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
There is $65.00 in dimes and quarters. If there is 389 coins how many were dimes and how many were quarters?
\n" ); document.write( ":
\n" ); document.write( "d + q = 389
\n" ); document.write( "d = (389-q)
\n" ); document.write( ":
\n" ); document.write( ".10d + .25q = 65
\n" ); document.write( ":
\n" ); document.write( ".10(389-q) + .25q = 65
\n" ); document.write( ":
\n" ); document.write( "38.9 - .10q + .25q = 65
\n" ); document.write( ":
\n" ); document.write( ".15q = 65 - 38.9
\n" ); document.write( ":
\n" ); document.write( ".15q = 26.1
\n" ); document.write( "q = \"26.1%2F.15\"
\n" ); document.write( "q = 174 quarters
\n" ); document.write( ":
\n" ); document.write( "d = 389 - 174
\n" ); document.write( "d = 215 dimes
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions
\n" ); document.write( ".10(215) + .25(174) =
\n" ); document.write( "21.5 + 43.5 = 65.00 \n" ); document.write( "
\n" );