document.write( "Question 21612: How do I solve the logarithmic equation symbolically, log x^8=7+2 log x, we did not go over this in class?
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Algebra.Com's Answer #11526 by NaiXLG(18)\"\" \"About 
You can put this solution on YOUR website!
Ahhhh yes, logarithims, gotta love 'em...\r
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\n" ); document.write( "\n" ); document.write( "So, you begin by writing the original question\r
\n" ); document.write( "\n" ); document.write( "Solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"log+x%5E8+=+7+%2B+2log+x\"\r
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\n" ); document.write( "\n" ); document.write( "So, begin by rewriting the right logarithim as \"log+x%5E2\" because the properties of logarithims states that \"a+log+b+=+log+b%5Ea+\"\r
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\n" ); document.write( "\n" ); document.write( "So now you should have,\r
\n" ); document.write( "\n" ); document.write( "\"log+x%5E8+=+7+%2B+log+x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Bring the right logarithim to the left, so now we have all logs on the left, and all non-logs (constants) on the right.\r
\n" ); document.write( "\n" ); document.write( "\"log+x%5E8+-+log+x%5E2+=+7\"\r
\n" ); document.write( "\n" ); document.write( "Now using yet another property of logarithims, go ahead and simplify that left side into one single log....\r
\n" ); document.write( "\n" ); document.write( "Remember \"log+a+-+log+b+=+log%28a%2Fb%29\"\r
\n" ); document.write( "\n" ); document.write( "So, you'll have;\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%5E8%2Fx%5E2%29+=+7\"\r
\n" ); document.write( "\n" ); document.write( "Now, use your properties of exponents to simplify that log a little more...\r
\n" ); document.write( "\n" ); document.write( "Remember \"x%5Em%2Fx%5En+=+x%5E%28m-n%29\"\r
\n" ); document.write( "\n" ); document.write( "So,\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%5E6%29+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "Now, because the log has a base of ten, raise both sides of the equation to the tenth power....\r
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\n" ); document.write( "\n" ); document.write( "\"10%5Elog%28x%5E6%29+=+10%5E7\"\r
\n" ); document.write( "\n" ); document.write( "The log cancels out, and you're left with\r
\n" ); document.write( "\n" ); document.write( "\"x%5E6+=+10%5E7\"\r
\n" ); document.write( "\n" ); document.write( "Now simply take the 6th root of x to make it just a single x, and no more, and take the 6th root of \"10%5E7\" as well. (What you do to one side of the equation, you must do to the other.)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+10%5E%287%2F6%29\"\r
\n" ); document.write( "\n" ); document.write( "There you go....!\r
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