document.write( "Question 156377: How many 6 digit numbers can be made with any combination and permutation of 3 and 7? (e.g. 377777, 737777, 777333, 733733, 333337) \n" ); document.write( "
Algebra.Com's Answer #115176 by jim_thompson5910(35256)\"\" \"About 
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Let's try to find the number of combinations that 3 and 7 can make up for a two digit number.\r
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\n" ); document.write( "\n" ); document.write( "Let's try a smaller example. So let's use the numbers 3 and 7 to make a two digit number, three digit number, and a four digit number to see what is going on\r
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\n" ); document.write( "\n" ); document.write( "So let's list ALL of the possible two digit numbers:\r
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\n" ); document.write( "\n" ); document.write( "33
\n" ); document.write( "37
\n" ); document.write( "73
\n" ); document.write( "77\r
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\n" ); document.write( "\n" ); document.write( "So for a two digit number, there are 4 possible combinations\r
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\n" ); document.write( "\n" ); document.write( "So let's list ALL of the possible three digit numbers:\r
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\n" ); document.write( "\n" ); document.write( "333
\n" ); document.write( "337
\n" ); document.write( "373
\n" ); document.write( "377
\n" ); document.write( "733
\n" ); document.write( "737
\n" ); document.write( "773
\n" ); document.write( "777\r
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\n" ); document.write( "\n" ); document.write( "So for a three digit number, there are 8 different combinations.\r
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\n" ); document.write( "\n" ); document.write( "So let's list ALL of the possible four digit numbers:\r
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\n" ); document.write( "\n" ); document.write( "3333
\n" ); document.write( "3337
\n" ); document.write( "3373
\n" ); document.write( "3377
\n" ); document.write( "3733
\n" ); document.write( "3737
\n" ); document.write( "3773
\n" ); document.write( "3777
\n" ); document.write( "7333
\n" ); document.write( "7337
\n" ); document.write( "7373
\n" ); document.write( "7377
\n" ); document.write( "7733
\n" ); document.write( "7737
\n" ); document.write( "7773
\n" ); document.write( "7777\r
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\n" ); document.write( "\n" ); document.write( "So for a four digit number, there are 16 different combinations.\r
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\n" ); document.write( "\n" ); document.write( "Notice how the number of combinations keeps doubling (since 2 doubles to 4, 4 doubles to 8, 8 doubles to 16, etc...). \r
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\n" ); document.write( "\n" ); document.write( "So if we write out a 5 digit number only using 3 and 7, then we will list out 32 different combinations (which is double of 16). And finally for a six digit number, there will be 64 different combinations (which is double of 32). \r
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\n" ); document.write( "\n" ); document.write( "Note: the quicker way (ideally once you understand what's going on) is to use this formula \"y=2%5Ex\" where \"x\" is the number of digits and \"y\" is the number of unique number combinations.\r
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\n" ); document.write( "\n" ); document.write( "So in this case, \"x=6\" and \"y=2%5E6=64\". So once again, we get 64 different combinations.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So there are 64 unique 6 digit numbers that can be generated from just the two values 3 and 7.\r
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