document.write( "Question 156335: \"abx%5E2-%28a%5E2%2Bb%5E2%29x%2Bab=0\"then \n" ); document.write( "
Algebra.Com's Answer #115125 by oscargut(2103)\"\" \"About 
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\"abx%5E2-%28a%5E2%2Bb%5E2%29x%2Bab=0\"then\r
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\n" ); document.write( "\"x+=+%28%28a%5E2%2Bb%5E2%29+%2B-+sqrt%28+a%5E4-2a%5E2b%5E2%2Bb%5E4%29%29%2F%282%2Aab%29\"=
\n" ); document.write( "\"x+=+%28%28a%5E2%2Bb%5E2%29+%2B-+%28a%5E2-b%5E2%29%29%2F%282%2Aab%29+\"\r
\n" ); document.write( "\n" ); document.write( "then roots are: \"+2a%5E2%2F2ab+=a%2Fb\" and \"+2b%5E2%2F2ab+=b%2Fa\"\r
\n" ); document.write( "\n" ); document.write( "Solution: \"x=a%2Fb+\"and \"x=b%2Fa\"
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