document.write( "Question 156331: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #115121 by ptaylor(2198) You can put this solution on YOUR website! \n" ); document.write( "Let x=amount of time it takes all three working together to mix 20 drinks\r \n" ); document.write( "\n" ); document.write( "Steven mixes drinks at the rate of 4 drinks per min \n" ); document.write( "Sue mixes drinks at the rate of 2 drinks per min \n" ); document.write( "Jack mixes drinks at the rate of 20/15= 4/3 drinks per min\r \n" ); document.write( "\n" ); document.write( "Together they mix at the rate of 4+2+4/3= 7 1/3 drinks per min \n" ); document.write( "So, our equation to solve is: \n" ); document.write( "(7 1/3)x=20 or \n" ); document.write( "(22/3)x=20 multiply each side by 3 \n" ); document.write( "22x=60 \n" ); document.write( "x=2.73 min----------------------ans\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "Steven=4*2.73=10.91 drinks \n" ); document.write( "Sue=2*2.73=5.45 drinks \n" ); document.write( "Jack=(4/3)*2.73=3.64 drinks \n" ); document.write( "10.91+5.45+3.63=~~~~20 drinks\r \n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( " \n" ); document.write( " |