document.write( "Question 156279: One car travels 60mph and another one travels 45mph. If they start from the same place at the same time and travel in the same direction, after how many hours will the faster car be 50 miles ahead of the slower car? \n" ); document.write( "
Algebra.Com's Answer #115114 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "\"Car%5B1%5D=C%5B1%5D=60miles%2Fhour\" -----------------> faster car
\n" ); document.write( "\"Car%5B2%5D=C%5B2%5D=45miles%2Fhour\" ---------------------> slower car
\n" ); document.write( "Remember the situation, that \"C%5B1%5D\" is ahead of \"50miles\" at a certain \"highlight%28TIME%29\" that we're looking for. Putting that into equation, we need to add \"50miles%2Ftime\" to \"C%5B2%5D\" to cover the gap of \"C%5B1%5D\":
\n" ); document.write( "\"C%5B1%5D=C%5B2%5D%2B%2850miles%2Ftime%29\"
\n" ); document.write( "\"60%28mi%2Fhr%29=45%28mi%2Fhr%29%2B%2850mi%2Ftime%29\"
\n" ); document.write( "\"60%28mi%2Fhr%29-45%28mi%2Fhr%29=50%28mi%2Ftime%29\"
\n" ); document.write( "\"15%28mi%2Fhr%29=50%28mi%2Ftime%29\", cross multiply
\n" ); document.write( "\"15%28mi%29%28time%29=50%28mi%29%28hr%29\", divide both side by 15 to solve \"time\":
\n" ); document.write( "
\n" ); document.write( "\"time=3.3333333hrs\" ---> time=3 hours & 20mins
\n" ); document.write( "After \"highlight%283hours%29\" and \"highlight%2820minutes%29\", \"C%5B1%5D\" will be 50 miles ahead of \"C%5B2%5D\". In doubt? Let' see:
\n" ); document.write( "DISTANCE OF \"C%5B1%5D\" AFTER 3 hours & 20 minutes:
\n" ); document.write( "\"60%28miles%2Fcross%28hr%29%29%2A%283.3333333cross%28hours%29%29=200+miles\"
\n" ); document.write( "DISTANCE OF \"C%5B2%5D\" AFTER 3 hours & 20 minutes:
\n" ); document.write( "\"45%28miles%2Fcross%28hr%29%29%2A%283.3333333cross%28hours%29%29=150miles\"
\n" ); document.write( "\"C%5B1%5D-C%5B2%5D=200-150=50miles\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
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