document.write( "Question 156292: The width of a rectangle is 5ft. less then the length. The area of the rectangle is 176ft^2 Find the length and width of the rectabgle. I tried looking in my math and other books for examples and can't seem to find one.Please help
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Algebra.Com's Answer #115100 by kdr(11)![]() ![]() ![]() You can put this solution on YOUR website! Let L be the length of the rectangle. Let W be the width. \n" ); document.write( "The area of a rectangle is found by multiplying the length times the width. \n" ); document.write( "So, Area = LW \n" ); document.write( "But we know the area is 176 ft.^2, so we can write this equation: \n" ); document.write( "176 ft^2 = LW \n" ); document.write( "We also know the width is 5 ft. less than the length, so we can write this equation: \n" ); document.write( "W = L - 5 \n" ); document.write( "Now, substitute L-5 for W in the first equation: \n" ); document.write( "176 = L(L-5) \n" ); document.write( "176 = L^2 - 5L \n" ); document.write( "0 = L^2 - 5L -176 \n" ); document.write( "Factoring gives us: \n" ); document.write( "0 = (L + 11)(L - 16) \n" ); document.write( "So, either \n" ); document.write( "L + 11 = 0 \n" ); document.write( "giving \n" ); document.write( "L = -11 \n" ); document.write( "or \n" ); document.write( "L - 16 = 0 \n" ); document.write( "giving \n" ); document.write( "L = 16\r \n" ); document.write( "\n" ); document.write( "Since the length of the rectangle cannot be a negative value, the length, L, is 16. \n" ); document.write( "Since W = L - 5, \n" ); document.write( "W = 16 - 5 \n" ); document.write( "W = 11\r \n" ); document.write( "\n" ); document.write( "The length of the rectangle is 16 feet, the width is 11 feet.\r \n" ); document.write( "\n" ); document.write( "Checking: \n" ); document.write( "Area = L*W \n" ); document.write( "176 ft^2 = (16 ft)(11 ft) \n" ); document.write( "176 ft^2 = 176 ft^2 \n" ); document.write( " |