document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23079>Question 23079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution of citric acid that is 20% acid and another solution of 80% citric acid. She plans to mix these solutions together to make 200 liters of a new solution that is 50% acid. How many liters of each solution does she need to mix. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11510 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon%21><B>stanbon!(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon%21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Follow the acid.<BR>\n" );
document.write( "Start with 20%x acid<BR>\n" );
document.write( "Add 80%(200-x) acid<BR>\n" );
document.write( "End up with 50%(200)acid<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "20x +80(200-x) = 50(200)<BR>\n" );
document.write( "20x +16000 - 80x = 10000<BR>\n" );
document.write( "            -60x = -6000<BR>\n" );
document.write( "x = 100 liters of 20% solution<BR>\n" );
document.write( "200-x= 100 liters of 80% solution\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );