document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156207>Question 156207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mike and Colin run around a track a 450 meter track in opposite directions. They start at the same point and start at the same time. Mike's speed is 2.0 m/s and Colins speed is 2.5 m/s.  How far will colin run when they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115076 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 450=2t+2.5t<BR>\n" );
document.write( "450=4.5t<BR>\n" );
document.write( "t=450/4.5<BR>\n" );
document.write( "t=100 running time<BR>\n" );
document.write( "2.5*t=250 meters for Colin.<BR>\n" );
document.write( "2*100=200 meters for Mike.<BR>\n" );
document.write( " </SPAN>\n" );
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