document.write( "Question 156043: Write an equation of the line containing the given point and perpendicular to the given line.
\n" ); document.write( "(6,-2); 7x+6y=5
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Algebra.Com's Answer #115062 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
(6,-2); 7x+6y=5
\n" ); document.write( "6y=-7x+5
\n" ); document.write( "y=-7x/6+5/6 this line has a slope=-7/6. (red line)
\n" ); document.write( "A perpendicular line has a slope=6/7.
\n" ); document.write( "-2=6*6/7+b
\n" ); document.write( "-2=36/7+b
\n" ); document.write( "b=-2-36/7
\n" ); document.write( "b=(-2*7-36)/7
\n" ); document.write( "b=(-14-36)/7
\n" ); document.write( "b=-50/7
\n" ); document.write( "Thus the equation of the perpendicular line through (6,-2)is:
\n" ); document.write( "y=6x/7-50/7 (green line).
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-7x%2F6+%2B5%2F6%2C+6x%2F7+-50%2F7%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -7x/6 +5/6 and 6x/7 -50/7).
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