document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156179>Question 156179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of the straight line passing through ((2/5),(3/7)) and perpendicular to y+8x=2x+7  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115056 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of the straight line passing through ((2/5),(3/7)) and perpendicular to y+8x=2x+7 <BR>\n" );
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document.write( "1st, find the slope of y+8x=2x+7.<BR>\n" );
document.write( "y = -6x+7<BR>\n" );
document.write( "That's the \"slope intercept\" form, y = mx+b, so the slope is -6.<BR>\n" );
document.write( "The slope of a line perpendicular will have slope of the negative inverse, or 1/6.<BR>\n" );
document.write( "Use that and the point to find the equation.<BR>\n" );
document.write( "y-y1 = m*(x-x1)<BR>\n" );
document.write( "y-3/7 = (1/6)*(x - 2/5)<BR>\n" );
document.write( "Multiply by 210 to get rid of fractions<BR>\n" );
document.write( "210y - 90 = 35*(x - 2/5)<BR>\n" );
document.write( "210y - 90 = 35x -14<BR>\n" );
document.write( "35x - 210y = -76     (standard form)<BR>\n" );
document.write( "y = (1/6)x + 38/105  (slope intercept form)<BR>\n" );
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