document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156177>Question 156177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not figure out how to do algebric word problems. Not one. \r<BR>\n" );
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document.write( "If 2 is added to five times a number, the result is equal to 5 more than four times the number. find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #115052 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=115052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just take it step-by-step as you read the problem:<BR>\n" );
document.write( "\"If 2 is added (+2) to five times a number (5*n), the result is (=) to 5 more (+5) than four times the number (4*n)\"<BR>\n" );
document.write( "So we put this altogether to get:<BR>\n" );
document.write( "2+5n = 5+4n Now that you have an equation in which the variable, n, stands for the number that you are to find, you can solve it for n.<BR>\n" );
document.write( "2+5n = 5+4n Subtract 4n from both sides.<BR>\n" );
document.write( "2+5n-4n = 5+4n-4n Simplify this by combining like-terms.<BR>\n" );
document.write( "2+n = 5 Now subtract 2 from both sides.<BR>\n" );
document.write( "2-2+n = 5-2 Simplify.<BR>\n" );
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