document.write( "Question 22975: line segmant ab is congruent to bc and cd and ad (that is abcd is a rhombus)prove that line segmant ac is perpendicular to line segmant bd (hint: use detour) \n" ); document.write( "
Algebra.Com's Answer #11503 by venugopalramana(3286)\"\" \"About 
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LET ABCD BE THE RHOMBUS.WITH AB=BC=CD=DA.JOIN DIAGONALS AC AND BD. LET THEM MEET AT O.
\n" ); document.write( "IN TRIANGLES ABC AND ADC , WE HAVE
\n" ); document.write( "AB=AD...GIVEN
\n" ); document.write( "BC=DC...GIVEN
\n" ); document.write( "AC=AC....GIVEN
\n" ); document.write( "SO THEY ARE CONGRUENT.SO ANGLE BAC = ANGLE DAC ..
\n" ); document.write( "NOW CONSIDER TRIANGLES AOB AND AOD
\n" ); document.write( "AO=AO...COMMON SIDE
\n" ); document.write( "AB=AD...GIVEN
\n" ); document.write( "ANGLE BAC= ANGLE BAO=ANGLE DAC = ANGLE DAO...FROM ABOVE
\n" ); document.write( "SO THEY ARE CONGRUENT.
\n" ); document.write( "SO ANGLE AOD =ANGLE AOB ....BUT THEIR SUM IS 180 ...A STRAIGHT ANGLE
\n" ); document.write( "HENCE ANGLE AOD=ANGLE AOB=90..SIMILARLY ANGLE DOC = ANGLE ANGLE BOC=90 \n" ); document.write( "
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