document.write( "Question 156161: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:\r
\n" ); document.write( "\n" ); document.write( "What is g(x) = f^-1(x) if f(x) = 1/2 x?\r
\n" ); document.write( "\n" ); document.write( "a. g(x) = 0
\n" ); document.write( "b. g(x) = -2x
\n" ); document.write( "c. g(x) = 1/2x^-1
\n" ); document.write( "d. g(x) = 2x
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Algebra.Com's Answer #115028 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Is the function \"f%28x%29=%281%2F2%29x\" ?\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%281%2F2%29x\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x\" Replace \"f%28x%29\" with \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%281%2F2%29y\" Switch \"x\" and \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=y\" Multiply both sides by 2 to solve for \"y\"\r
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\n" ); document.write( "\n" ); document.write( "So after solving for \"y\", we get \"y=2x\". So the inverse function is \r
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\n" ); document.write( "\n" ); document.write( "Is the function \"f%28x%29=%281%29%2F%282x%29\" ?\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%281%29%2F%282x%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%29%2F%282x%29\" Replace \"f%28x%29\" with \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%281%29%2F%282y%29\" Switch \"x\" and \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"2xy=1\" Multiply both sides by \"2y\" \r
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\n" ); document.write( "\n" ); document.write( "\"y=1%2F%282x%29\" Divide both sides by \"2x\" to solve for \"y\"\r
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\n" ); document.write( "\n" ); document.write( "So after solving for \"y\", we get \"y=1%2F%282x%29\". So the inverse function is
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