document.write( "Question 156145This question is from textbook college algebra
\n" ); document.write( ": thank you in advance for helping me with this problem!!!
\n" ); document.write( "f(x)=x^2+x
\n" ); document.write( "I factored out the x to get: x(x+1)and then got x can not equal 0 or -1 for the domain. Am I on the right track? Thank you.
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Algebra.Com's Answer #115010 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Are you trying to find the domain of \"f%28x%29=x%5E2%2Bx\" ??\r
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\n" ); document.write( "\n" ); document.write( "If you are, then notice how there is no division by a variable or a square root of a variable. This means that we don't have to worry about division by zero or taking the square root of a negative number. So this means that we can plug in any number into \"f%28x%29=x%5E2%2Bx\" and it will result in a real number.\r
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\n" ); document.write( "\n" ); document.write( "So the domain is all real numbers. \r
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\n" ); document.write( "\n" ); document.write( "The domain in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Also the domain in interval notation is ()
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