document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156093>Question 156093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really need help with this one. I need to evaluate:\r<BR>\n" );
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document.write( "{6(5 - 7) + 2}^3 ÷ (-2) - 3^2. <BR>\n" );
document.write( "I got it all wrong the first time and I'd like to see what you come up with. Thanks so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114986 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> {6(5 - 7) + 2}^3 ÷ (-2) - 3^2<BR>\n" );
document.write( "={6*(-2) + 2)}^3/[(-2) - 3^2]<BR>\n" );
document.write( "= {-12 + 2}^3/[-2 -9]<BR>\n" );
document.write( "= {-10}^3/[-11]<BR>\n" );
document.write( "=100/11<BR>\n" );
document.write( "= 9.090909... if all the brackets are in the right places.  There's some ambiguity in the denominator.<BR>\n" );
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