document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=156116>Question 156116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114971 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Steven can mix 20 drinks in 5 minutes,then he mix 4 drinks in a minute <BR>\n" );
document.write( "Sue can mix 20 drinks in 10 minutes,then he mix 2 drinks in a minute <BR>\n" );
document.write( "Jack can mix 20 drinks in 15 minutes, then he mix 4/3 drinks in a minute \r<BR>\n" );
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document.write( "then in a minute working together they mix 4+2+4/3 drinks =22/3 drinks <BR>\n" );
document.write( "then 22/3 = 1 minute<BR>\n" );
document.write( "     20  =  x minutes\r<BR>\n" );
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document.write( "x=20/(22/3)=60/22=30/11\r<BR>\n" );
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document.write( "Answer: 30/11 minutes (aprox 2.73 minutes)\r<BR>\n" );
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