document.write( "Question 156028: Jack is three times as old as Megan was two years ago. The sum of their ages three years ago was 16.\r
\n" ); document.write( "\n" ); document.write( "How old are Jack and Megan now?\r
\n" ); document.write( "\n" ); document.write( "Please show the work on how you approach the answer. Thank you!
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Algebra.Com's Answer #114919 by stanbon(75887)\"\" \"About 
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Jack is three times as old as Megan was two years ago.
\n" ); document.write( "The sum of their ages three years ago was 16.
\n" ); document.write( "How old are Jack and Megan now?
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\n" ); document.write( "Now DATA:
\n" ); document.write( "Jack is J yrs old.
\n" ); document.write( "Megan is M yrs old.
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "J = 3(M-2) = 3M-6
\n" ); document.write( "(J-3) + (M-3) = 16
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\n" ); document.write( "Substitute J = 3M-6 into the 2nd equation to solve for \"M\":
\n" ); document.write( "(3M-6-3) + (M-3) = 16
\n" ); document.write( "4M - 12 = 16
\n" ); document.write( "4M = 28
\n" ); document.write( "M = 7 (megan's age now)
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\n" ); document.write( "J= 3*7-6 = 15 (Jack's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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