document.write( "Question 155990: y^2=x+1. Find the vertex, x and y intercepts, and sketch the graph. Please help, I have no idea what to do with this!!! \n" ); document.write( "
Algebra.Com's Answer #114904 by stanbon(75887)\"\" \"About 
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y^2=x+1. Find the vertex, x and y intercepts, and sketch the graph.
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\n" ); document.write( "(y-0)^2 + 4(1/4)(x+1)\r
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\n" ); document.write( "Vertex: (-1,0)
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\n" ); document.write( "x-intercept: Let y = 0, then x+1 = 0; x = -1
\n" ); document.write( "x-intercept: (-1,0)
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\n" ); document.write( "y-intercept: Let x = 0, then y^2 = 1; y = +/-1
\n" ); document.write( "y-intercepts: (0,1) and (0,-1)
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\n" ); document.write( "Graph:
\n" ); document.write( "x = y^2-1
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\n" ); document.write( "Plot the vertex at (-1,0)
\n" ); document.write( "Plot the y-intercepts at (0,1) and (0,-1)
\n" ); document.write( "The graph is a parabola opening to the right.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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