document.write( "Question 155941: A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly the 300 miles when flying against the wind. What is the plane's speed in still air? \n" ); document.write( "
Algebra.Com's Answer #114870 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let r=rate(speed) of plane in still air \n" ); document.write( "Let r1=rate (speed) of tailwind\r \n" ); document.write( "\n" ); document.write( "With tailwind: 300=(r+r1)*1\r \n" ); document.write( "\n" ); document.write( "300=r+r1-------------------------------eq1\r \n" ); document.write( "\n" ); document.write( "Against tailwind: 300=(r-r1)*2\r \n" ); document.write( "\n" ); document.write( "300=2r-2r1------------------------------eq2 \n" ); document.write( "multiply eq1 by 2 and then add it to eq2:\r \n" ); document.write( "\n" ); document.write( "600=2r+2r1----------eq1a \n" ); document.write( "300=2r-2r1-------------eq2\r \n" ); document.write( "\n" ); document.write( "900=4r divide each side by 4 \n" ); document.write( "r=225 mph---------------------------speed of plane in still air\r \n" ); document.write( "\n" ); document.write( "substitute r=225 mph into eq1 \n" ); document.write( "300=225+r1 subtract 225 from each side \r \n" ); document.write( "\n" ); document.write( "300-225=225-225+r1 collect like terms\r \n" ); document.write( "\n" ); document.write( "75=r1 or \n" ); document.write( "r1=75 mph----------------------speed of wind\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "300=(225+75)*1 \n" ); document.write( "300=300 \n" ); document.write( "and \n" ); document.write( "300=(225-75)*2 \n" ); document.write( "300=150*2 \n" ); document.write( "300=300\r \n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( " \n" ); document.write( " |