document.write( "Question 155832: Please help me on my homework\r
\n" ); document.write( "\n" ); document.write( "prove the identity\r
\n" ); document.write( "\n" ); document.write( "sec^6A-tan^6A=1+3sec^2Atan^2A
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Algebra.Com's Answer #114867 by Edwin McCravy(20062)\"\" \"About 
You can put this solution on YOUR website!
\"Sec%5E6A-Tan%5E6A\" = \"1%2B3Sec%5E2A%2ATan%5E2A\"
\n" ); document.write( "\"%28Sec%5E2A%29%5E3-Tan%5E6A\"
\n" ); document.write( "\"%281%2BTan%5E2A%29%5E3-Tan%5E6A\"
\n" ); document.write( "\"%281%2BTan%5E2A%29%281%2BTan%5E2A%29%281%2BTan%5E2A%29-Tan%5E6A\"
\n" ); document.write( "\"%281%2BTan%5E2A%29%281%2B2Tan%5E2A%2BTan%5E4A%29-Tan%5E6\"
\n" ); document.write( "\"%281%2B2Tan%5E2A%2BTan%5E4A%2BTan%5E2A%2B2Tan%5E4A%2BTan%5E6A%29-Tan%5E6A\"
\n" ); document.write( "\"1%2B2Tan%5E2A%2BTan%5E4A%2BTan%5E2A%2B2Tan%5E4A%2BTan%5E6A-Tan%5E6A\"
\n" ); document.write( "\"1%2B3Tan%5E2A%2B3Tan%5E4A\"
\n" ); document.write( "\"1%2B3Tan%5E2A%2A%281%2BTan%5E2A%29\"
\n" ); document.write( "\"1%2B3Tan%5E2A%2ASec%5E2A\"
\n" ); document.write( "\"1%2B3Sec%5E2A%2ATan%5E2A\"\r
\n" ); document.write( "\n" ); document.write( "Edwin
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