document.write( "Question 155910: Ann has a 32 ounce bowl of M&M's on her cofee table. The candies are 50% blue M&M's. She eats some of the M&M's (which are 50% blue), then fills the bowl back to 32 ounces with a package of M&M's that contains 20% blue ones. If the resulting full bowl (32 ounces) contains 40% blue M&M's, how many ounces did she eat?\r
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document.write( "So far, I know that the original bowl had 16 ounces of blue M&M's (32 oz x 50% = 16 oz). The bag she used to refill with had 6.4 oz (32 oz x 20% = 6.4 oz). The final result was 12.8 ounces of blue M&M's (32 oz x 40% = 12.8) I dont know if that info is relevant to the problem or if I am looking at it all wrong. \n" );
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Algebra.Com's Answer #114864 by stanbon(75887) ![]() You can put this solution on YOUR website! Ann has a 32 ounce bowl of M&M's on her cofee table. \n" ); document.write( "The candies are 50% blue M&M's. \n" ); document.write( "----- \n" ); document.write( "She starts with 32 oz ; 16 oz is blue \n" ); document.write( "She eats x oz. of which half is blue \n" ); document.write( "------------------ \n" ); document.write( "She now has 32-x oz ; she has 16-(x/2) blue \n" ); document.write( "----------------- \n" ); document.write( "She puts back x oz of which 1/5 is blue \n" ); document.write( "----------------- \n" ); document.write( "She now has 32 oz ; she has 16-(x/2) + (1/5)x blue \n" ); document.write( "------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "blue - blue + blue = blue \n" ); document.write( "16 - (x/2) + (1/5)x = 0.40*32 \n" ); document.write( "16 + (1/5 - 1/2)x = 12.8 \n" ); document.write( "(-3/10)x = -3.2 \n" ); document.write( "x = 32/3 \n" ); document.write( "x = 10 2/3 oz. \n" ); document.write( "She ate 10 2/3 oz \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |