document.write( "Question 155827: can somebody please help me understand how to go about this question:
\n" ); document.write( "Find the term not involving y in the expansion of (1/y^3+y^2)^5. Please help!! Thank you.
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Algebra.Com's Answer #114861 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
A general expansion would be,
\n" ); document.write( "\"%28a+%2B+b%29%5E5+=+a%5E5%2B5a%5E4b+%2B+10a%5E3b%5E2+%2B10a%5E2b%5E3+%2B5ab%5E4+%2B+b%5E5\"
\n" ); document.write( "Let \"a=y%5E-3\" and \"b=y%5E2\", the term not involving y will have y canceling out in the numerator and denominator.
\n" ); document.write( "\"a%5E2=y%5E-6\"
\n" ); document.write( "\"b%5E3=y%5E6\"
\n" ); document.write( "\"a%5E2b%5E3=y%5E-6%2Ay%5E6=y%5E%28-6%2B6%29=1\"
\n" ); document.write( "That's the third term of the expansion, \"10a%5E2b%5E3=10%281%29=10\".
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