document.write( "Question 22890: The time necessary T to make an enlargement of a photo negative varies directly as the area of the enlargement. If 108 seconds are required to make a 3-by-4 inch enlargement, find the time required to make a 6-by-8 inch enlargement.
\n" ); document.write( "A. 384 seconds
\n" ); document.write( "B. 528 seconds
\n" ); document.write( "C. 480 seconds
\n" ); document.write( "D. 432 seconds
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Algebra.Com's Answer #11486 by rapaljer(4671)\"\" \"About 
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Step 1: Write an equation relating the variables using k for a constant:
\n" ); document.write( "T=kA\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Substitute one complete set of variables and solve for k:
\n" ); document.write( "T=kA
\n" ); document.write( "108 = k*12\r
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\n" ); document.write( "\n" ); document.write( "Divide by 12:
\n" ); document.write( "\"108%2F12=+%2812k%29%2F12\"
\n" ); document.write( "\"9=k\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Use this value of k to answer the question about T.\r
\n" ); document.write( "\n" ); document.write( "The question is to find T when A= 6*8 = 48:
\n" ); document.write( "T=9A
\n" ); document.write( "T= 9*48
\n" ); document.write( "T= 432 seconds, which would be D.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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