document.write( "Question 155882: y=√(3y+10)please help solve \n" ); document.write( "
Algebra.Com's Answer #114832 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
y = \"sqrt%283y%2B10%29\"
\n" ); document.write( "Square both sides:
\n" ); document.write( "y^2 = 3y + 10
\n" ); document.write( "Arrange as a quadratic equation on the left:
\n" ); document.write( "y^2 - 3y - 10 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(y-5)(y+2) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "y = +5
\n" ); document.write( "y = -2
\n" ); document.write( ":
\n" ); document.write( "Always test solutions in the original equation, especially when dealing with radicals
\n" ); document.write( "y = 5:
\n" ); document.write( "5 = \"sqrt%283%285%29%2B10%29\"
\n" ); document.write( "5 = \"sqrt%2825%29\" a good solution
\n" ); document.write( ":
\n" ); document.write( "y =-2:
\n" ); document.write( " -2 = \"sqrt%283%28-2%29%2B10%29\"
\n" ); document.write( "-2 = \"sqrt%284%29\"
\n" ); document.write( "-2 does not = +2, not a solution
\n" ); document.write( "
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