document.write( "Question 155862: From a lighthouse L an aircraft carrier A is 15km away on a bearing of 112 degrees and a submarine S is 26 km away on a bearing of 200 degrees. Find\r
\n" ); document.write( "\n" ); document.write( "a) the distance between A and S\r
\n" ); document.write( "\n" ); document.write( "b) the bearing of A from S\r
\n" ); document.write( "\n" ); document.write( "Please I need desperate help...its due later today!!!!
\n" ); document.write( "

Algebra.Com's Answer #114814 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
From a lighthouse L an aircraft carrier A is 15km away on a bearing of 112 degrees and a submarine S is 26 km away on a bearing of 200 degrees. Find
\n" ); document.write( "a) the distance between A and S
\n" ); document.write( "b) the bearing of A from S
\n" ); document.write( "----------------
\n" ); document.write( "Sketch it, and you'll see that the angle ALS is 88 degs (200 - 112).
\n" ); document.write( "Use the law of cosines to find side AS.
\n" ); document.write( "\"c%5E2+=+a%5E2+%2B+b%5E2+-+2ab%2Acos%2888%29\"
\n" ); document.write( "\"c%5E2+=+15%5E2+%2B+26%5E2+-+2%2A15%2A26%2Acos%2888%29\"
\n" ); document.write( "\"c%5E2+=+225+%2B+676+-+780%2A0.0348995\"
\n" ); document.write( "\"c%5E2+=+873.778...\"
\n" ); document.write( "c = 29.5597 (distance AS)
\n" ); document.write( "--------------
\n" ); document.write( "Now find the angle LAS by the law of sines
\n" ); document.write( "sin(LAS)/26 = sin(88)/29.5597
\n" ); document.write( "Angle LAS = 61.53 degs
\n" ); document.write( "-----------------
\n" ); document.write( "The heading from the AC to the Lighthouse is 112 + 180 = 292
\n" ); document.write( "Subtract 61.53 from that, for a heading of
\n" ); document.write( "230.47, just slightly west of southwest.
\n" ); document.write( "
\n" ); document.write( "
\n" );