document.write( "Question 155862: From a lighthouse L an aircraft carrier A is 15km away on a bearing of 112 degrees and a submarine S is 26 km away on a bearing of 200 degrees. Find\r
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document.write( "a) the distance between A and S\r
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document.write( "b) the bearing of A from S\r
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document.write( "Please I need desperate help...its due later today!!!! \n" );
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Algebra.Com's Answer #114814 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! From a lighthouse L an aircraft carrier A is 15km away on a bearing of 112 degrees and a submarine S is 26 km away on a bearing of 200 degrees. Find \n" ); document.write( "a) the distance between A and S \n" ); document.write( "b) the bearing of A from S \n" ); document.write( "---------------- \n" ); document.write( "Sketch it, and you'll see that the angle ALS is 88 degs (200 - 112). \n" ); document.write( "Use the law of cosines to find side AS. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "c = 29.5597 (distance AS) \n" ); document.write( "-------------- \n" ); document.write( "Now find the angle LAS by the law of sines \n" ); document.write( "sin(LAS)/26 = sin(88)/29.5597 \n" ); document.write( "Angle LAS = 61.53 degs \n" ); document.write( "----------------- \n" ); document.write( "The heading from the AC to the Lighthouse is 112 + 180 = 292 \n" ); document.write( "Subtract 61.53 from that, for a heading of \n" ); document.write( "230.47, just slightly west of southwest. \n" ); document.write( " \n" ); document.write( " |