document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155846>Question 155846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to find dy/dx on this question but before i can do that i have to simplify the expression using log laws.\r<BR>\n" );
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document.write( "I've taken logs so that log y= 1/3log(x^2-8) + 1/2log(x^3+1) - log(x^6 -7x + 5)<BR>\n" );
document.write( "but i am unsure how to simplify it further.<BR>\n" );
document.write( "Any assistance would be appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114812 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I've taken logs so that log y= 1/3log(x^2-8) + 1/2log(x^3+1) - log(x^6 -7x + 5)<BR>\n" );
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document.write( "You have correctly taken the log of both sides of the equation.<BR>\n" );
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document.write( "Assuming you mean log and not ln, remember that the derivative of <BR>\n" );
document.write( "ln(u) = 1/u u' where u' is the derivative wrt x<BR>\n" );
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document.write( "But log(u) can be written as (1/ln(10))ln(u)<BR>\n" );
document.write( "So the derivative of log(u) is (1/ln(10)*(1/u)u'<BR>\n" );
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document.write( "Using that fact you should be able to find the derivative of your log equation:\r<BR>\n" );
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document.write( "(1/ln(10)(dy/dx) = (1/3)(1/ln(10))(1/(x^2-8)(2x) etc.<BR>\n" );
document.write( "Write it all out then solve for dy/dx.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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