document.write( "Question 155856: 100p-4000/100p=.3 solve for p \n" ); document.write( "

Algebra.Com's Answer #114807 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28100p-4000%29%2F%28100p%29=.3\"$
\n" ); document.write( " $\"100p-4000=.3%28100p%29\"$
\n" ); document.write( " $\"100p-4000=30p\"$
\n" ); document.write( " $\"70p=4000\"$
\n" ); document.write( " $\"p=4000%2F70=400%2F7\"$
\n" ); document.write( "Approximately,
\n" ); document.write( " $\"p=57.14\"$ \n" ); document.write( "

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