document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155744>Question 155744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine how much water is required to dilute 15 liters of a solution that is 12 %dye so that a 5% dye solution is obtained? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114805 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of water required\r<BR>\n" );
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document.write( "Now we know that the amount of pure dye before the water is added(0.12*15) has to equal the amount of pure dye after the water is added(0.05(15+x))<BR>\n" );
document.write( "So, our equation to solve is:\r<BR>\n" );
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document.write( "0.12*15=0.05*(15+x) get rid of parens and simplify<BR>\n" );
document.write( "1.8=0.75+0.05x  subtract 0.75 froom each side<BR>\n" );
document.write( "1.8-0.75=0.75-0.75+0.05x  collect like terms<BR>\n" );
document.write( "1.05=0.05x divide each side by 0.05<BR>\n" );
document.write( "x=21 liters-----------------------------amount of water needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.12*15=0.05*36<BR>\n" );
document.write( "1.8=1.8\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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