document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155737>Question 155737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what on earth does this mean? How do I either solve it or simplify it or WRITE it?\r<BR>\n" );
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document.write( "5x^2 + 28x - 10 / x + 6  or 5x^2 + 28x - 10 over x + 6\r<BR>\n" );
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document.write( "thank you, if you know any idea of what I should do with this, I'd appreciate it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114804 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You would perform a synthetic division of the two polynomials.<BR>\n" );
document.write( "Similar to long division but the columns signify terms of degrees of x.<BR>\n" );
document.write( "To get 5x^2, I would need to multiply (x+6) by 5x.<BR>\n" );
document.write( "That would give me 5x^2+30x.<BR>\n" );
document.write( "Subtract that from 5x^2+28x-10 would leave -2x-10.<BR>\n" );
document.write( "to get -2x, I would need to multiply (x+6) by (-2)<BR>\n" );
document.write( "That would give me -2x-12.<BR>\n" );
document.write( "Subtract that from -2x-10 would leave 2.<BR>\n" );
document.write( "I can't go any further.<BR>\n" );
document.write( "Gather up all of the terms and the remainder.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285x%5E2%2B28x-10%29%2F%28x%2B6%29=5x-2%2B2%2F%28x%2B6%29 ALIGN=MIDDLE  ALT=\"%285x%5E2%2B28x-10%29%2F%28x%2B6%29=5x-2%2B2%2F%28x%2B6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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