document.write( "Question 152103: i need to solve this question algebracially\r
\n" );
document.write( "\n" );
document.write( "3/4x-2/5y=2
\n" );
document.write( "1/2x-3/5y=-2 \n" );
document.write( "
Algebra.Com's Answer #114803 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 1. \n" ); document.write( "2. \n" ); document.write( "I'm not a big fan of fractions so I usually multiply both equations to get rid of denominators. \n" ); document.write( "Multiply eq. 1 by 20 and eq. 2 by 10. \n" ); document.write( "1. \n" ); document.write( "1. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "2. \n" ); document.write( "2. \n" ); document.write( "Now use the elimination method to solve. \n" ); document.write( "If I multiply eq. 2 by (-3) and add to eq. 1, I can get rid of x, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Using eq. 1, \n" ); document.write( "1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Check the answer with the original equations. \n" ); document.write( "1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "True. \n" ); document.write( "I'll leave it to you to verify that eq. 2 works also. \n" ); document.write( " |