document.write( "Question 22904: ab/5-3=3b/10+9 \n" ); document.write( "
Algebra.Com's Answer #11479 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"ab%2F5-3=3b%2F10%2B9\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Are you solving for for a or for b? Either way, let's clear the fraction by multiplying both sides by the LCD for the equation, which is 10.\r
\n" ); document.write( "\n" ); document.write( "\"10%2A%28ab%2F5%29-10%2A3=10%2A%283b%2F10%29%2B+10%2A9\"
\n" ); document.write( "\"2ab-30+=+3b+%2B+90\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add +30 to both sides:
\n" ); document.write( "\"2ab-30%2B30+=+3b+%2B+90+%2B+30\"
\n" ); document.write( "\"2ab+=+3b+%2B+120\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now, IF you are solving for a, you need to get rid of the 2b. Divide both sides by 2b:\r
\n" ); document.write( "\n" ); document.write( "\"%282ab%29%2F%282b%29=+%283b%2B120%29%2F%282b%29\"
\n" ); document.write( "\"a=+%283b%2B120%29%2F%282b%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "IF you are solving for b, you need to get all the b terms on the left side, so subtract 3b from each side:
\n" ); document.write( "\"2ab+=+3b+%2B+120\"
\n" ); document.write( "\"2ab+-+3b+=+120\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factor out the b, so as to get all the b's in one place:
\n" ); document.write( "\"+b%282a-3%29+=+120\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide both sides by (2a-3):
\n" ); document.write( "\"b=+120%2F%282a-3%29+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );