document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155814>Question 155814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A candy store owner wishes to mix 30 pounds of candy worth $6.00 per pound with nuts worth $3.00 per pound to get a mixture worth $5.00 per pound. How many pounds of nuts must he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114783 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of nuts needed\r<BR>\n" );
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document.write( "Now we know that the value of the nuts(3x) and candy(6*30) before they are mixed has to equal the value of the nuts and candy after they are mixed(5*(30+x)), ok? ($ are understood) So, our equation to solve is:<BR>\n" );
document.write( "3x+6*30=5(30+x)  get rid of parens and simplify\r<BR>\n" );
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document.write( "3x+180=150+5x  subtract 150 and also 3x from each side\r<BR>\n" );
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document.write( "3x-3x+180-150=150-150+5x-3x  collect like terms\r<BR>\n" );
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document.write( "30=2x  divide each side by 2\r<BR>\n" );
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document.write( "x=15 lb-------------amount of nuts needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "3*15+6*30=5*45<BR>\n" );
document.write( "45+180=225<BR>\n" );
document.write( "225=225\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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