document.write( "Question 155816: How many pounds of an alloy containing 32% silver must be melted with 25 pounds of an alloy containing 48% silver to obtain and alloy containing 42% silver? \n" ); document.write( "

Algebra.Com's Answer #114782 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=amount of 32% silver alloy needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure silver in the 32% alloy (0.32x) plus the amount of pure silver in the 48% alloy (0.48*25) has to equal the amount of pure silver in the final mixture(0.42*(25+x)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.32x+0.48*25=0.42(25+x) get rid of parens and simplify\r
\n" ); document.write( "\n" ); document.write( "0.32x+12=10.5+0.42x subtract 0.32x and also 10.5 from each side\r
\n" ); document.write( "\n" ); document.write( "0.32x-0.32x+12-10.5=10.5-10.5+0.42x-0.32x collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.10x=1.5 divide each side by 0.10
\n" ); document.write( "x=15 lb----------------------------amount of 32% silver alloy needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.32*15+0.48*25=0.42*40
\n" ); document.write( "4.8+12=16.8
\n" ); document.write( "16.8=16.8\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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