document.write( "Question 155811This question is from textbook elementary and intermediate algebra
\n" ); document.write( ": Cansomeone help me with this? #44. Fast food. If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?
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Algebra.Com's Answer #114769 by jojo14344(1513) $\"\"$ $\"About$

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If $\"4%2F5=0.80%2A100\"$ or 80% of doctors prefer fast food, then at convention of 445 doctors, 80% of which prefer that OR, $\"445%2A0.80=356doctors\"$ .
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