document.write( "Question 155798This question is from textbook
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document.write( ": Use dimensional to change
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document.write( "A.50 Meters per second to Kilometer per hour?
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document.write( "B.0.025 day to second?
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document.write( "C.1200 Ounces to tons (16 oz = 1ib;2000 = 1 ton). \n" );
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Algebra.Com's Answer #114761 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use dimensional to change \n" ); document.write( "A.50 Meters per second to Kilometer per hour? \n" ); document.write( "(50 meter/sec)(kilometer/1000 meters)(3600 sec/1 hour) \n" ); document.write( "= [50*1*3600/1*10000*1] kilometers/hour \n" ); document.write( "= 180000/10000 km/hr \n" ); document.write( "= 18 km/hr \n" ); document.write( "---------------------\r \n" ); document.write( "\n" ); document.write( "B.0.025 day to second? \n" ); document.write( "0.025 days(24 hrs./day)(3600 sec/hr) \n" ); document.write( "= (0.025*24 *3600/1*1*1) seconds \n" ); document.write( "= 2160 seconds \n" ); document.write( "---------------------\r \n" ); document.write( "\n" ); document.write( "C.1200 Ounces to tons (16 oz = 1 lb;2000 = 1 ton). \n" ); document.write( "1200 ounces (1 lb/16 oz)(1 ton/2000 lbs) \n" ); document.write( "= [1200*1*1/16*2000] tons \n" ); document.write( "= 0.003813 tons \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |