document.write( "Question 155798This question is from textbook
\n" ); document.write( ": Use dimensional to change
\n" ); document.write( "A.50 Meters per second to Kilometer per hour?
\n" ); document.write( "B.0.025 day to second?
\n" ); document.write( "C.1200 Ounces to tons (16 oz = 1ib;2000 = 1 ton).
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Algebra.Com's Answer #114761 by stanbon(75887)\"\" \"About 
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Use dimensional to change
\n" ); document.write( "A.50 Meters per second to Kilometer per hour?
\n" ); document.write( "(50 meter/sec)(kilometer/1000 meters)(3600 sec/1 hour)
\n" ); document.write( "= [50*1*3600/1*10000*1] kilometers/hour
\n" ); document.write( "= 180000/10000 km/hr
\n" ); document.write( "= 18 km/hr
\n" ); document.write( "---------------------\r
\n" ); document.write( "\n" ); document.write( "B.0.025 day to second?
\n" ); document.write( "0.025 days(24 hrs./day)(3600 sec/hr)
\n" ); document.write( "= (0.025*24 *3600/1*1*1) seconds
\n" ); document.write( "= 2160 seconds
\n" ); document.write( "---------------------\r
\n" ); document.write( "\n" ); document.write( "C.1200 Ounces to tons (16 oz = 1 lb;2000 = 1 ton).
\n" ); document.write( "1200 ounces (1 lb/16 oz)(1 ton/2000 lbs)
\n" ); document.write( "= [1200*1*1/16*2000] tons
\n" ); document.write( "= 0.003813 tons
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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