document.write( "Question 155724: If anyone can help me...
\n" ); document.write( "The width of a rectangle is 4ft. less than the length. The area is 5ft^2. Find the length and the width.\r
\n" ); document.write( "\n" ); document.write( "How do I do this?
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Algebra.Com's Answer #114754 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
W=L-4
\n" ); document.write( "AREA=L*W
\n" ); document.write( "5=L(L-4)
\n" ); document.write( "5=L^2-4L
\n" ); document.write( "L^2-4L-5=0
\n" ); document.write( "(L-5)(L+1)=0
\n" ); document.write( "L-5=0
\n" ); document.write( "L=5 FOR THE LENGTH
\n" ); document.write( "5-4=1 FOR THE WIDTH.
\n" ); document.write( "pROOF:
\n" ); document.write( "5=5*1
\n" ); document.write( "5=5
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