document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155758>Question 155758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you would please help me solve this word problem:\r<BR>\n" );
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document.write( "The length of a rectangle is 1 inch less than three times the width. If the length  is increased by 6 inches and the width is increased by 5 inches, then the length will be twice the width. Find the dimensions of the rectangle.\r<BR>\n" );
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document.write( "So far this is what I have done: Let x=the width<BR>\n" );
document.write( "Since the length = 3x-1, I added the 6 inches and double the width.<BR>\n" );
document.write( "I have for an equation:<BR>\n" );
document.write( "(3x-1)+6 = 2x<BR>\n" );
document.write( "However when I solved it it turned out to be:<BR>\n" );
document.write( "3x+5=2x<BR>\n" );
document.write( "x+5=0<BR>\n" );
document.write( "x=-5<BR>\n" );
document.write( "But, as you can see, I can't have a negative dimension in a rectangle! D:!!\r<BR>\n" );
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document.write( "So please, can you point out what I did wrong ;-;? Please and thank you!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114726 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L = length and W = width.<BR>\n" );
document.write( "L = 3W-1 and<BR>\n" );
document.write( "L+6 = 2(W+5) Substitute the L from the above equation.<BR>\n" );
document.write( "(3W-1)+6 = 2(W+5) Simplify.<BR>\n" );
document.write( "3W+5 = 2W+10 Subtract 2W from both sides.<BR>\n" );
document.write( "W+5 = 10 Subtract 5 from both sides.<BR>\n" );
document.write( "W = 5 inches and<BR>\n" );
document.write( "L = 3W-1<BR>\n" );
document.write( "L = 3(5)-1<BR>\n" );
document.write( "L = 15-1<BR>\n" );
document.write( "L = 14 inches. </SPAN>\n" );
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