document.write( "Question 155746: if the sum of three consecutive odd integers is 237 then what are the integers \n" ); document.write( "
Algebra.Com's Answer #114720 by Electrified_Levi(103)\"\" \"About 
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hi, hope I can help,
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\n" ); document.write( "if the sum of three consecutive odd integers is 237 then what are the integers
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\n" ); document.write( "This is a pretty easy problem
\n" ); document.write( "First, you have to know the variables
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\n" ); document.write( "consecutive means \"in order\" (example: 1, 2, 3, ... ) here is another example: (25, 26, 27, ... )
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\n" ); document.write( "consecutive odd means \"in order, but they have to be odd numbers\" (examples: 3, 5, 7, 9, ... ) or ( 107, 109, 111, 113, ... )
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\n" ); document.write( "Since this is our first number, we can name it \"x\"
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\n" ); document.write( "Our second number would be \"x+2\" ( we have three consecutive odd integers ,meaning, if the first number is odd, you have to add 2 more to get the next odd number( example: let's say our \"x\" was 5, our second number would be \"x+2\", we replace \"x\" it will become \"5+2\" or \"7\", our first odd number is 5, our second is 7)
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\n" ); document.write( "Our third number is \"x+4\" (if second number is odd, have to add 2 to get the third odd number
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\n" ); document.write( "Your first number will always be \"x\"
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\n" ); document.write( "If you are trying to find the consecutive numbers(not consecutive odd), you add 1 for each number ( first number = \"x\", second = \"x+1\", third = \"x+2\", fourth = \"x + 3\", ... )
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\n" ); document.write( "If you are finding consecutive odd( or even) numbers, you add 2 for each number
\n" ); document.write( "( first number always = \"x\") ( first number = \"x\", second number = \"x + 2\", third number = \"x + 4\", fourth number = \"x + 6\", ... )
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\n" ); document.write( "Since we are finding consecutive odd integers, our three numbers are( remember we start with \"x\" and add 2 each time)
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\n" ); document.write( "First number = \"x\"
\n" ); document.write( "Second number = \"x + 2\"
\n" ); document.write( "Third number = \"x + 4\"
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\n" ); document.write( "Since we know our three variables, we can know put them in a formula
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\n" ); document.write( "if the sum of three consecutive odd integers is 237 then what are the integers
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\n" ); document.write( "First number = \"x\"
\n" ); document.write( "Second number = \"x + 2\"
\n" ); document.write( "Third number = \"x + 4\"
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\n" ); document.write( "Our fomula = \"+%28x%29+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29+=+237+\"
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\n" ); document.write( "Now all we need to do is solve for \"x\"
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\n" ); document.write( "We can get rid of the parentheses, \"+x+%2B+x+%2B+2+%2B+x+%2B+4+=+237+\"
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\n" ); document.write( "We will reorder the numbers, \"+x+%2B+x+%2B+x+%2B+4+%2B+2+=+237+\"
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\n" ); document.write( "we will now combine like terms
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\n" ); document.write( "\"+%28x+%2B+x+%2B+x%29+%2B+%284+%2B+2%29+=+237+\" = \"+3x+%2B+6+=+237+\"
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\n" ); document.write( "we will now move \"6\" to the right side
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\n" ); document.write( "\"+3x+%2B+6+-+6+=+237+-+6+\" = \"+3x+=+231+\"
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\n" ); document.write( "We will divide each side by \"3\" to get \"x\"
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\n" ); document.write( "\"+3x%2F3+=+231%2F3+\" = \"+x+=+231%2F3+\" = \"+x+=+77+\"
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\n" ); document.write( "We found that our first odd consecutive number(x) = 77
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\n" ); document.write( "Our second number = \"x + 2\" ( replace \"x\" with 77) = \"77 + 2\" = 79
\n" ); document.write( "Our third number = \"x + 4\" ( replace \"x\" with 77) = \"77 + 4\" = 81
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\n" ); document.write( "We can check by replacing \"x\" with 77 in our original equation
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\n" ); document.write( "\"+%28x%29+%2B+%28x+%2B+2%29+%2B+%28x+%2B+4%29+=+237+\"
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\n" ); document.write( "\"+%2877%29+%2B+%2877+%2B+2%29+%2B+%2877+%2B+4%29+=+237+\"
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\n" ); document.write( "\"+%2877%29+%2B+%2879%29+%2B+%2881%29+=+237+\"
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\n" ); document.write( "\"+237+=+237+\" ( True )
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\n" ); document.write( "Our three numbers are
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\n" ); document.write( "1st = \"+77+\"
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\n" ); document.write( "2nd = \"+79+\"
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\n" ); document.write( "3rd = \"+81+\"
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\n" ); document.write( "Hope I helped, Levi \n" ); document.write( "
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