document.write( "Question 155739: how do you find the perimeter and area of a square whose side is y-3?
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Algebra.Com's Answer #114716 by jim_thompson5910(35256)\"\" \"About 
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Perimeter of a Square: \"P=4s\" where \"P\" is the perimeter and \"s\" is the side length\r
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\n" ); document.write( "\n" ); document.write( "\"P=4s\" Start with the general formula for the perimeter of a square\r
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\n" ); document.write( "\n" ); document.write( "\"P=4%28y-3%29\" Plug in the given side length of \"s=y-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"P=4y-12\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "So the perimeter is \"P=4y-12\"\r
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\n" ); document.write( "\n" ); document.write( "Area of a Square: \"A=s%5E2\" where \"A\" is the area and \"s\" is the side length\r
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\n" ); document.write( "\n" ); document.write( "\"A=s%5E2\" Start with the general formula for the area of a square\r
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\n" ); document.write( "\n" ); document.write( "\"A=%28y-3%29%5E2\" Plug in the given side length of \"s=y-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=y%5E2-3y-3y%2B9\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"A=y%5E2-6y%2B9\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=y%5E2-6y%2B9\"
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