document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=155666>Question 155666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 10% alcohol solution must be mixed with 70 liters of a 90% solution to get a 30% solution?\r<BR>\n" );
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document.write( "Thanks in advance for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114703 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of liters of 10% alcohol solution to be added to 70 liters of 90% alcohol solution to get (x+70) liters of 30% alcohol solution.<BR>\n" );
document.write( "After changing the percentages to their decimal equivalents, we can express this as:<BR>\n" );
document.write( "(0.1)x + (0.9)(70) = (x+70)(0.3) Simplify this and solve for x.<BR>\n" );
document.write( "0.1x+63 = 0.3x+21 Subtract 0.1x from both sides.<BR>\n" );
document.write( "63 = 0.2x+21 Subtract 21 from both sides.<BR>\n" );
document.write( "42 = 0.2x Finally, divide both sides by 0.2<BR>\n" );
document.write( "x = 210 liters.<BR>\n" );
document.write( "You would need to mix 210 liters of a 10% alcohol solution to 70 liters of 90% alcohol solution to obtain 280 (210+70) liters of 30% alcohol solution. </SPAN>\n" );
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