document.write( "Question 22903: (y-8)/2=(y+10)/5 \n" ); document.write( "
Algebra.Com's Answer #11466 by mmm4444bot(95)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "(y - 8)/2 = (y + 10)/5\r
\n" ); document.write( "\n" ); document.write( "Clear the fractions by multiplying both sides of this equation by 10 (the LCM of 2 and 5).\r
\n" ); document.write( "\n" ); document.write( "5*(y - 8) = 2*(y + 10)\r
\n" ); document.write( "\n" ); document.write( "Use the distributive property to get rid of the parentheses.\r
\n" ); document.write( "\n" ); document.write( "5*y - 40 = 2*y + 20\r
\n" ); document.write( "\n" ); document.write( "Combine like terms; subtract 2*y from both sides and add 40 to both sides.\r
\n" ); document.write( "\n" ); document.write( "5*y - 2*y = 20 + 40\r
\n" ); document.write( "\n" ); document.write( "3*y = 60\r
\n" ); document.write( "\n" ); document.write( "Solve for y by dividing both sides by 3.\r
\n" ); document.write( "\n" ); document.write( "y = 60/3\r
\n" ); document.write( "\n" ); document.write( "y = 20\r
\n" ); document.write( "\n" ); document.write( "Check the answer by substituting 20 for y in the original equation, and then simplify to see if you end up with a true statement.\r
\n" ); document.write( "\n" ); document.write( "(20 - 8)/2 = (20 + 10)/5\r
\n" ); document.write( "\n" ); document.write( "12/2 = 30/5\r
\n" ); document.write( "\n" ); document.write( "6 = 6\r
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